58 lines
1.8 KiB
Python
58 lines
1.8 KiB
Python
#!/usr/bin/env python
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"""This runs 'ls -l' on a remote host using SSH. At the prompts enter hostname,
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user, and password.
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$Id: sshls.py 489 2007-11-28 23:40:34Z noah $
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"""
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import pexpect
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import getpass
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import os
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def ssh_command(user, host, password, command):
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"""This runs a command on the remote host. This could also be done with the
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pxssh class, but this demonstrates what that class does at a simpler level.
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This returns a pexpect.spawn object. This handles the case when you try to
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connect to a new host and ssh asks you if you want to accept the public key
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fingerprint and continue connecting. """
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ssh_newkey = 'Are you sure you want to continue connecting'
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child = pexpect.spawn('ssh -l %s %s %s' % (user, host, command))
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i = child.expect([pexpect.TIMEOUT, ssh_newkey, 'password: '])
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if i == 0: # Timeout
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print 'ERROR!'
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print 'SSH could not login. Here is what SSH said:'
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print child.before, child.after
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return None
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if i == 1: # SSH does not have the public key. Just accept it.
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child.sendline('yes')
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child.expect('password: ')
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i = child.expect([pexpect.TIMEOUT, 'password: '])
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if i == 0: # Timeout
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print 'ERROR!'
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print 'SSH could not login. Here is what SSH said:'
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print child.before, child.after
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return None
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child.sendline(password)
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return child
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def main():
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host = raw_input('Hostname: ')
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user = raw_input('User: ')
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password = getpass.getpass('Password: ')
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child = ssh_command(user, host, password, '/bin/ls -l')
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child.expect(pexpect.EOF)
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print child.before
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if __name__ == '__main__':
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try:
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main()
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except Exception as e:
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print str(e)
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traceback.print_exc()
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os._exit(1)
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