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解决偶尔的只有2个参数（第三个为0）导致搜不到回复归0的

This commit is contained in:
枫谷剑仙 2020-09-01 13:42:59 +08:00
parent c570722bf3
commit 8ed31a9cf2
1 changed files with 4 additions and 4 deletions
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8
languages/zh-CN.js
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@ -1888,12 +1888,12 @@ function parseBigNumber(number)
{name:"回复力 buff（顶降回复）",function:cards=>cards.filter(card=>{
const searchTypeArray = [50,90];
const skill = Skills[card.activeSkillId];
if (searchTypeArray.includes(skill.type) && skill.params.slice(1,-1).includes(5))
if (searchTypeArray.includes(skill.type) && skill.params.slice(1,skill.params.length>2?undefined:-1).includes(5))
return true;
else if (skill.type == 116 || skill.type == 118){
const subskills = skill.params.map(id=>Skills[id]);
return subskills.some(subskill=>
searchTypeArray.includes(subskill.type) && subskill.params.slice(1,-1).includes(5)
searchTypeArray.includes(subskill.type) && subskill.params.slice(1,skill.params.length>2?undefined:-1).includes(5)
);
}
})},
@ -1905,7 +1905,7 @@ function parseBigNumber(number)
];
const skill = Skills[card.activeSkillId];
if ((skill.type==88 || skill.type==92) || //类型的
(skill.type==50 || skill.type==90) && skill.params.slice(1,-1).some(sk=>sk!=5) || //属性的，要排除回复力
(skill.type==50 || skill.type==90) && skill.params.slice(1,skill.params.length>2?undefined:-1).some(sk=>sk!=5) || //属性的，要排除回复力
skill.type==156 && skill.params[4] == 2 || skill.type==168 //宝石姬的
)
return true;
@ -1913,7 +1913,7 @@ function parseBigNumber(number)
const subskills = skill.params.map(id=>Skills[id]);
return subskills.some(subskill=>
(subskill.type==88 || subskill.type==92) || //类型的
(subskill.type==50 || subskill.type==90) && subskill.params.slice(1,-1).some(sk=>sk!=5) || //属性的，要排除回复力
(subskill.type==50 || subskill.type==90) && subskill.params.slice(1,subskill.params.length>2?undefined:-1).some(sk=>sk!=5) || //属性的，要排除回复力
subskill.type==156 && subskill.params[4] == 2 || subskill.type==168 //宝石姬的
);
}