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			244 lines
		
	
	
		
			8.0 KiB
		
	
	
	
		
			Go
		
	
	
	
			
		
		
	
	
			244 lines
		
	
	
		
			8.0 KiB
		
	
	
	
		
			Go
		
	
	
	
| // Copyright 2010 The Go Authors. All rights reserved.
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| // Use of this source code is governed by a BSD-style
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| // license that can be found in the LICENSE file.
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| 
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| package math
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| 
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| // The original C code, the long comment, and the constants
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| // below are from FreeBSD's /usr/src/lib/msun/src/s_expm1.c
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| // and came with this notice.  The go code is a simplified
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| // version of the original C.
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| //
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| // ====================================================
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| // Copyright (C) 1993 by Sun Microsystems, Inc. All rights reserved.
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| //
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| // Developed at SunPro, a Sun Microsystems, Inc. business.
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| // Permission to use, copy, modify, and distribute this
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| // software is freely granted, provided that this notice
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| // is preserved.
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| // ====================================================
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| //
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| // expm1(x)
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| // Returns exp(x)-1, the exponential of x minus 1.
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| //
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| // Method
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| //   1. Argument reduction:
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| //      Given x, find r and integer k such that
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| //
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| //               x = k*ln2 + r,  |r| <= 0.5*ln2 ~ 0.34658
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| //
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| //      Here a correction term c will be computed to compensate
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| //      the error in r when rounded to a floating-point number.
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| //
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| //   2. Approximating expm1(r) by a special rational function on
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| //      the interval [0,0.34658]:
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| //      Since
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| //          r*(exp(r)+1)/(exp(r)-1) = 2+ r**2/6 - r**4/360 + ...
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| //      we define R1(r*r) by
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| //          r*(exp(r)+1)/(exp(r)-1) = 2+ r**2/6 * R1(r*r)
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| //      That is,
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| //          R1(r**2) = 6/r *((exp(r)+1)/(exp(r)-1) - 2/r)
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| //                   = 6/r * ( 1 + 2.0*(1/(exp(r)-1) - 1/r))
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| //                   = 1 - r**2/60 + r**4/2520 - r**6/100800 + ...
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| //      We use a special Reme algorithm on [0,0.347] to generate
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| //      a polynomial of degree 5 in r*r to approximate R1. The
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| //      maximum error of this polynomial approximation is bounded
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| //      by 2**-61. In other words,
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| //          R1(z) ~ 1.0 + Q1*z + Q2*z**2 + Q3*z**3 + Q4*z**4 + Q5*z**5
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| //      where   Q1  =  -1.6666666666666567384E-2,
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| //              Q2  =   3.9682539681370365873E-4,
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| //              Q3  =  -9.9206344733435987357E-6,
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| //              Q4  =   2.5051361420808517002E-7,
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| //              Q5  =  -6.2843505682382617102E-9;
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| //      (where z=r*r, and the values of Q1 to Q5 are listed below)
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| //      with error bounded by
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| //          |                  5           |     -61
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| //          | 1.0+Q1*z+...+Q5*z   -  R1(z) | <= 2
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| //          |                              |
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| //
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| //      expm1(r) = exp(r)-1 is then computed by the following
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| //      specific way which minimize the accumulation rounding error:
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| //                             2     3
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| //                            r     r    [ 3 - (R1 + R1*r/2)  ]
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| //            expm1(r) = r + --- + --- * [--------------------]
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| //                            2     2    [ 6 - r*(3 - R1*r/2) ]
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| //
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| //      To compensate the error in the argument reduction, we use
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| //              expm1(r+c) = expm1(r) + c + expm1(r)*c
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| //                         ~ expm1(r) + c + r*c
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| //      Thus c+r*c will be added in as the correction terms for
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| //      expm1(r+c). Now rearrange the term to avoid optimization
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| //      screw up:
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| //                      (      2                                    2 )
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| //                      ({  ( r    [ R1 -  (3 - R1*r/2) ]  )  }    r  )
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| //       expm1(r+c)~r - ({r*(--- * [--------------------]-c)-c} - --- )
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| //                      ({  ( 2    [ 6 - r*(3 - R1*r/2) ]  )  }    2  )
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| //                      (                                             )
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| //
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| //                 = r - E
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| //   3. Scale back to obtain expm1(x):
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| //      From step 1, we have
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| //         expm1(x) = either 2**k*[expm1(r)+1] - 1
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| //                  = or     2**k*[expm1(r) + (1-2**-k)]
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| //   4. Implementation notes:
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| //      (A). To save one multiplication, we scale the coefficient Qi
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| //           to Qi*2**i, and replace z by (x**2)/2.
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| //      (B). To achieve maximum accuracy, we compute expm1(x) by
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| //        (i)   if x < -56*ln2, return -1.0, (raise inexact if x!=inf)
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| //        (ii)  if k=0, return r-E
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| //        (iii) if k=-1, return 0.5*(r-E)-0.5
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| //        (iv)  if k=1 if r < -0.25, return 2*((r+0.5)- E)
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| //                     else          return  1.0+2.0*(r-E);
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| //        (v)   if (k<-2||k>56) return 2**k(1-(E-r)) - 1 (or exp(x)-1)
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| //        (vi)  if k <= 20, return 2**k((1-2**-k)-(E-r)), else
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| //        (vii) return 2**k(1-((E+2**-k)-r))
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| //
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| // Special cases:
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| //      expm1(INF) is INF, expm1(NaN) is NaN;
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| //      expm1(-INF) is -1, and
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| //      for finite argument, only expm1(0)=0 is exact.
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| //
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| // Accuracy:
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| //      according to an error analysis, the error is always less than
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| //      1 ulp (unit in the last place).
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| //
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| // Misc. info.
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| //      For IEEE double
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| //          if x >  7.09782712893383973096e+02 then expm1(x) overflow
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| //
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| // Constants:
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| // The hexadecimal values are the intended ones for the following
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| // constants. The decimal values may be used, provided that the
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| // compiler will convert from decimal to binary accurately enough
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| // to produce the hexadecimal values shown.
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| //
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| 
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| // Expm1 returns e**x - 1, the base-e exponential of x minus 1.
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| // It is more accurate than Exp(x) - 1 when x is near zero.
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| //
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| // Special cases are:
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| //	Expm1(+Inf) = +Inf
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| //	Expm1(-Inf) = -1
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| //	Expm1(NaN) = NaN
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| // Very large values overflow to -1 or +Inf.
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| 
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| //extern expm1
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| func libc_expm1(float64) float64
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| 
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| func Expm1(x float64) float64 {
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| 	return libc_expm1(x)
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| }
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| 
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| func expm1(x float64) float64 {
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| 	const (
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| 		Othreshold = 7.09782712893383973096e+02 // 0x40862E42FEFA39EF
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| 		Ln2X56     = 3.88162421113569373274e+01 // 0x4043687a9f1af2b1
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| 		Ln2HalfX3  = 1.03972077083991796413e+00 // 0x3ff0a2b23f3bab73
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| 		Ln2Half    = 3.46573590279972654709e-01 // 0x3fd62e42fefa39ef
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| 		Ln2Hi      = 6.93147180369123816490e-01 // 0x3fe62e42fee00000
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| 		Ln2Lo      = 1.90821492927058770002e-10 // 0x3dea39ef35793c76
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| 		InvLn2     = 1.44269504088896338700e+00 // 0x3ff71547652b82fe
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| 		Tiny       = 1.0 / (1 << 54)            // 2**-54 = 0x3c90000000000000
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| 		// scaled coefficients related to expm1
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| 		Q1 = -3.33333333333331316428e-02 // 0xBFA11111111110F4
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| 		Q2 = 1.58730158725481460165e-03  // 0x3F5A01A019FE5585
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| 		Q3 = -7.93650757867487942473e-05 // 0xBF14CE199EAADBB7
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| 		Q4 = 4.00821782732936239552e-06  // 0x3ED0CFCA86E65239
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| 		Q5 = -2.01099218183624371326e-07 // 0xBE8AFDB76E09C32D
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| 	)
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| 
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| 	// special cases
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| 	switch {
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| 	case IsInf(x, 1) || IsNaN(x):
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| 		return x
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| 	case IsInf(x, -1):
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| 		return -1
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| 	}
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| 
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| 	absx := x
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| 	sign := false
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| 	if x < 0 {
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| 		absx = -absx
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| 		sign = true
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| 	}
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| 
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| 	// filter out huge argument
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| 	if absx >= Ln2X56 { // if |x| >= 56 * ln2
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| 		if absx >= Othreshold { // if |x| >= 709.78...
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| 			return Inf(1) // overflow
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| 		}
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| 		if sign {
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| 			return -1 // x < -56*ln2, return -1.0
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| 		}
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| 	}
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| 
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| 	// argument reduction
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| 	var c float64
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| 	var k int
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| 	if absx > Ln2Half { // if  |x| > 0.5 * ln2
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| 		var hi, lo float64
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| 		if absx < Ln2HalfX3 { // and |x| < 1.5 * ln2
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| 			if !sign {
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| 				hi = x - Ln2Hi
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| 				lo = Ln2Lo
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| 				k = 1
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| 			} else {
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| 				hi = x + Ln2Hi
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| 				lo = -Ln2Lo
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| 				k = -1
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| 			}
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| 		} else {
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| 			if !sign {
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| 				k = int(InvLn2*x + 0.5)
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| 			} else {
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| 				k = int(InvLn2*x - 0.5)
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| 			}
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| 			t := float64(k)
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| 			hi = x - t*Ln2Hi // t * Ln2Hi is exact here
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| 			lo = t * Ln2Lo
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| 		}
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| 		x = hi - lo
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| 		c = (hi - x) - lo
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| 	} else if absx < Tiny { // when |x| < 2**-54, return x
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| 		return x
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| 	} else {
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| 		k = 0
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| 	}
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| 
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| 	// x is now in primary range
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| 	hfx := 0.5 * x
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| 	hxs := x * hfx
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| 	r1 := 1 + hxs*(Q1+hxs*(Q2+hxs*(Q3+hxs*(Q4+hxs*Q5))))
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| 	t := 3 - r1*hfx
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| 	e := hxs * ((r1 - t) / (6.0 - x*t))
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| 	if k != 0 {
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| 		e = (x*(e-c) - c)
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| 		e -= hxs
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| 		switch {
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| 		case k == -1:
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| 			return 0.5*(x-e) - 0.5
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| 		case k == 1:
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| 			if x < -0.25 {
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| 				return -2 * (e - (x + 0.5))
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| 			}
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| 			return 1 + 2*(x-e)
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| 		case k <= -2 || k > 56: // suffice to return exp(x)-1
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| 			y := 1 - (e - x)
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| 			y = Float64frombits(Float64bits(y) + uint64(k)<<52) // add k to y's exponent
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| 			return y - 1
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| 		}
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| 		if k < 20 {
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| 			t := Float64frombits(0x3ff0000000000000 - (0x20000000000000 >> uint(k))) // t=1-2**-k
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| 			y := t - (e - x)
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| 			y = Float64frombits(Float64bits(y) + uint64(k)<<52) // add k to y's exponent
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| 			return y
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| 		}
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| 		t := Float64frombits(uint64((0x3ff - k) << 52)) // 2**-k
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| 		y := x - (e + t)
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| 		y += 1
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| 		y = Float64frombits(Float64bits(y) + uint64(k)<<52) // add k to y's exponent
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| 		return y
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| 	}
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| 	return x - (x*e - hxs) // c is 0
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| }
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