forked from OSchip/llvm-project
				
			
		
			
				
	
	
		
			1252 lines
		
	
	
		
			47 KiB
		
	
	
	
		
			C++
		
	
	
	
			
		
		
	
	
			1252 lines
		
	
	
		
			47 KiB
		
	
	
	
		
			C++
		
	
	
	
//===---- MachineOutliner.cpp - Outline instructions -----------*- C++ -*-===//
 | 
						|
//
 | 
						|
//                     The LLVM Compiler Infrastructure
 | 
						|
//
 | 
						|
// This file is distributed under the University of Illinois Open Source
 | 
						|
// License. See LICENSE.TXT for details.
 | 
						|
//
 | 
						|
//===----------------------------------------------------------------------===//
 | 
						|
///
 | 
						|
/// \file
 | 
						|
/// Replaces repeated sequences of instructions with function calls.
 | 
						|
///
 | 
						|
/// This works by placing every instruction from every basic block in a
 | 
						|
/// suffix tree, and repeatedly querying that tree for repeated sequences of
 | 
						|
/// instructions. If a sequence of instructions appears often, then it ought
 | 
						|
/// to be beneficial to pull out into a function.
 | 
						|
///
 | 
						|
/// This was originally presented at the 2016 LLVM Developers' Meeting in the
 | 
						|
/// talk "Reducing Code Size Using Outlining". For a high-level overview of
 | 
						|
/// how this pass works, the talk is available on YouTube at
 | 
						|
///
 | 
						|
/// https://www.youtube.com/watch?v=yorld-WSOeU
 | 
						|
///
 | 
						|
/// The slides for the talk are available at
 | 
						|
///
 | 
						|
/// http://www.llvm.org/devmtg/2016-11/Slides/Paquette-Outliner.pdf
 | 
						|
///
 | 
						|
/// The talk provides an overview of how the outliner finds candidates and
 | 
						|
/// ultimately outlines them. It describes how the main data structure for this
 | 
						|
/// pass, the suffix tree, is queried and purged for candidates. It also gives
 | 
						|
/// a simplified suffix tree construction algorithm for suffix trees based off
 | 
						|
/// of the algorithm actually used here, Ukkonen's algorithm.
 | 
						|
///
 | 
						|
/// For the original RFC for this pass, please see
 | 
						|
///
 | 
						|
/// http://lists.llvm.org/pipermail/llvm-dev/2016-August/104170.html
 | 
						|
///
 | 
						|
/// For more information on the suffix tree data structure, please see
 | 
						|
/// https://www.cs.helsinki.fi/u/ukkonen/SuffixT1withFigs.pdf
 | 
						|
///
 | 
						|
//===----------------------------------------------------------------------===//
 | 
						|
#include "llvm/ADT/DenseMap.h"
 | 
						|
#include "llvm/ADT/Statistic.h"
 | 
						|
#include "llvm/ADT/Twine.h"
 | 
						|
#include "llvm/CodeGen/MachineFrameInfo.h"
 | 
						|
#include "llvm/CodeGen/MachineFunction.h"
 | 
						|
#include "llvm/CodeGen/MachineInstrBuilder.h"
 | 
						|
#include "llvm/CodeGen/MachineModuleInfo.h"
 | 
						|
#include "llvm/CodeGen/Passes.h"
 | 
						|
#include "llvm/IR/IRBuilder.h"
 | 
						|
#include "llvm/Support/Allocator.h"
 | 
						|
#include "llvm/Support/Debug.h"
 | 
						|
#include "llvm/Support/raw_ostream.h"
 | 
						|
#include "llvm/Target/TargetInstrInfo.h"
 | 
						|
#include "llvm/Target/TargetMachine.h"
 | 
						|
#include "llvm/Target/TargetRegisterInfo.h"
 | 
						|
#include "llvm/Target/TargetSubtargetInfo.h"
 | 
						|
#include <functional>
 | 
						|
#include <map>
 | 
						|
#include <sstream>
 | 
						|
#include <tuple>
 | 
						|
#include <vector>
 | 
						|
 | 
						|
#define DEBUG_TYPE "machine-outliner"
 | 
						|
 | 
						|
using namespace llvm;
 | 
						|
 | 
						|
STATISTIC(NumOutlined, "Number of candidates outlined");
 | 
						|
STATISTIC(FunctionsCreated, "Number of functions created");
 | 
						|
 | 
						|
namespace {
 | 
						|
 | 
						|
/// \brief An individual sequence of instructions to be replaced with a call to
 | 
						|
/// an outlined function.
 | 
						|
struct Candidate {
 | 
						|
 | 
						|
  /// Set to false if the candidate overlapped with another candidate.
 | 
						|
  bool InCandidateList = true;
 | 
						|
 | 
						|
  /// The start index of this \p Candidate.
 | 
						|
  size_t StartIdx;
 | 
						|
 | 
						|
  /// The number of instructions in this \p Candidate.
 | 
						|
  size_t Len;
 | 
						|
 | 
						|
  /// The index of this \p Candidate's \p OutlinedFunction in the list of
 | 
						|
  /// \p OutlinedFunctions.
 | 
						|
  size_t FunctionIdx;
 | 
						|
 | 
						|
  /// \brief The number of instructions that would be saved by outlining every
 | 
						|
  /// candidate of this type.
 | 
						|
  ///
 | 
						|
  /// This is a fixed value which is not updated during the candidate pruning
 | 
						|
  /// process. It is only used for deciding which candidate to keep if two
 | 
						|
  /// candidates overlap. The true benefit is stored in the OutlinedFunction
 | 
						|
  /// for some given candidate.
 | 
						|
  unsigned Benefit = 0;
 | 
						|
 | 
						|
  Candidate(size_t StartIdx, size_t Len, size_t FunctionIdx)
 | 
						|
      : StartIdx(StartIdx), Len(Len), FunctionIdx(FunctionIdx) {}
 | 
						|
 | 
						|
  Candidate() {}
 | 
						|
 | 
						|
  /// \brief Used to ensure that \p Candidates are outlined in an order that
 | 
						|
  /// preserves the start and end indices of other \p Candidates.
 | 
						|
  bool operator<(const Candidate &RHS) const { return StartIdx > RHS.StartIdx; }
 | 
						|
};
 | 
						|
 | 
						|
/// \brief The information necessary to create an outlined function for some
 | 
						|
/// class of candidate.
 | 
						|
struct OutlinedFunction {
 | 
						|
 | 
						|
  /// The actual outlined function created.
 | 
						|
  /// This is initialized after we go through and create the actual function.
 | 
						|
  MachineFunction *MF = nullptr;
 | 
						|
 | 
						|
  /// A number assigned to this function which appears at the end of its name.
 | 
						|
  size_t Name;
 | 
						|
 | 
						|
  /// The number of candidates for this OutlinedFunction.
 | 
						|
  size_t OccurrenceCount = 0;
 | 
						|
 | 
						|
  /// \brief The sequence of integers corresponding to the instructions in this
 | 
						|
  /// function.
 | 
						|
  std::vector<unsigned> Sequence;
 | 
						|
 | 
						|
  /// The number of instructions this function would save.
 | 
						|
  unsigned Benefit = 0;
 | 
						|
 | 
						|
  /// \brief Set to true if candidates for this outlined function should be
 | 
						|
  /// replaced with tail calls to this OutlinedFunction.
 | 
						|
  bool IsTailCall = false;
 | 
						|
 | 
						|
  OutlinedFunction(size_t Name, size_t OccurrenceCount,
 | 
						|
                   const std::vector<unsigned> &Sequence,
 | 
						|
                   unsigned Benefit, bool IsTailCall)
 | 
						|
      : Name(Name), OccurrenceCount(OccurrenceCount), Sequence(Sequence),
 | 
						|
        Benefit(Benefit), IsTailCall(IsTailCall)
 | 
						|
        {}
 | 
						|
};
 | 
						|
 | 
						|
/// Represents an undefined index in the suffix tree.
 | 
						|
const size_t EmptyIdx = -1;
 | 
						|
 | 
						|
/// A node in a suffix tree which represents a substring or suffix.
 | 
						|
///
 | 
						|
/// Each node has either no children or at least two children, with the root
 | 
						|
/// being a exception in the empty tree.
 | 
						|
///
 | 
						|
/// Children are represented as a map between unsigned integers and nodes. If
 | 
						|
/// a node N has a child M on unsigned integer k, then the mapping represented
 | 
						|
/// by N is a proper prefix of the mapping represented by M. Note that this,
 | 
						|
/// although similar to a trie is somewhat different: each node stores a full
 | 
						|
/// substring of the full mapping rather than a single character state.
 | 
						|
///
 | 
						|
/// Each internal node contains a pointer to the internal node representing
 | 
						|
/// the same string, but with the first character chopped off. This is stored
 | 
						|
/// in \p Link. Each leaf node stores the start index of its respective
 | 
						|
/// suffix in \p SuffixIdx.
 | 
						|
struct SuffixTreeNode {
 | 
						|
 | 
						|
  /// The children of this node.
 | 
						|
  ///
 | 
						|
  /// A child existing on an unsigned integer implies that from the mapping
 | 
						|
  /// represented by the current node, there is a way to reach another
 | 
						|
  /// mapping by tacking that character on the end of the current string.
 | 
						|
  DenseMap<unsigned, SuffixTreeNode *> Children;
 | 
						|
 | 
						|
  /// A flag set to false if the node has been pruned from the tree.
 | 
						|
  bool IsInTree = true;
 | 
						|
 | 
						|
  /// The start index of this node's substring in the main string.
 | 
						|
  size_t StartIdx = EmptyIdx;
 | 
						|
 | 
						|
  /// The end index of this node's substring in the main string.
 | 
						|
  ///
 | 
						|
  /// Every leaf node must have its \p EndIdx incremented at the end of every
 | 
						|
  /// step in the construction algorithm. To avoid having to update O(N)
 | 
						|
  /// nodes individually at the end of every step, the end index is stored
 | 
						|
  /// as a pointer.
 | 
						|
  size_t *EndIdx = nullptr;
 | 
						|
 | 
						|
  /// For leaves, the start index of the suffix represented by this node.
 | 
						|
  ///
 | 
						|
  /// For all other nodes, this is ignored.
 | 
						|
  size_t SuffixIdx = EmptyIdx;
 | 
						|
 | 
						|
  /// \brief For internal nodes, a pointer to the internal node representing
 | 
						|
  /// the same sequence with the first character chopped off.
 | 
						|
  ///
 | 
						|
  /// This has two major purposes in the suffix tree. The first is as a
 | 
						|
  /// shortcut in Ukkonen's construction algorithm. One of the things that
 | 
						|
  /// Ukkonen's algorithm does to achieve linear-time construction is
 | 
						|
  /// keep track of which node the next insert should be at. This makes each
 | 
						|
  /// insert O(1), and there are a total of O(N) inserts. The suffix link
 | 
						|
  /// helps with inserting children of internal nodes.
 | 
						|
  ///
 | 
						|
  /// Say we add a child to an internal node with associated mapping S. The 
 | 
						|
  /// next insertion must be at the node representing S - its first character.
 | 
						|
  /// This is given by the way that we iteratively build the tree in Ukkonen's
 | 
						|
  /// algorithm. The main idea is to look at the suffixes of each prefix in the
 | 
						|
  /// string, starting with the longest suffix of the prefix, and ending with
 | 
						|
  /// the shortest. Therefore, if we keep pointers between such nodes, we can
 | 
						|
  /// move to the next insertion point in O(1) time. If we don't, then we'd
 | 
						|
  /// have to query from the root, which takes O(N) time. This would make the
 | 
						|
  /// construction algorithm O(N^2) rather than O(N).
 | 
						|
  ///
 | 
						|
  /// The suffix link is also used during the tree pruning process to let us
 | 
						|
  /// quickly throw out a bunch of potential overlaps. Say we have a sequence
 | 
						|
  /// S we want to outline. Then each of its suffixes contribute to at least
 | 
						|
  /// one overlapping case. Therefore, we can follow the suffix links
 | 
						|
  /// starting at the node associated with S to the root and "delete" those
 | 
						|
  /// nodes, save for the root. For each candidate, this removes
 | 
						|
  /// O(|candidate|) overlaps from the search space. We don't actually
 | 
						|
  /// completely invalidate these nodes though; doing that is far too
 | 
						|
  /// aggressive. Consider the following pathological string:
 | 
						|
  ///
 | 
						|
  /// 1 2 3 1 2 3 2 3 2 3 2 3 2 3 2 3 2 3
 | 
						|
  ///
 | 
						|
  /// If we, for the sake of example, outlined 1 2 3, then we would throw
 | 
						|
  /// out all instances of 2 3. This isn't desirable. To get around this,
 | 
						|
  /// when we visit a link node, we decrement its occurrence count by the
 | 
						|
  /// number of sequences we outlined in the current step. In the pathological
 | 
						|
  /// example, the 2 3 node would have an occurrence count of 8, while the
 | 
						|
  /// 1 2 3 node would have an occurrence count of 2. Thus, the 2 3 node
 | 
						|
  /// would survive to the next round allowing us to outline the extra
 | 
						|
  /// instances of 2 3.
 | 
						|
  SuffixTreeNode *Link = nullptr;
 | 
						|
 | 
						|
  /// The parent of this node. Every node except for the root has a parent.
 | 
						|
  SuffixTreeNode *Parent = nullptr;
 | 
						|
 | 
						|
  /// The number of times this node's string appears in the tree.
 | 
						|
  ///
 | 
						|
  /// This is equal to the number of leaf children of the string. It represents
 | 
						|
  /// the number of suffixes that the node's string is a prefix of.
 | 
						|
  size_t OccurrenceCount = 0;
 | 
						|
 | 
						|
  /// The length of the string formed by concatenating the edge labels from the
 | 
						|
  /// root to this node.
 | 
						|
  size_t ConcatLen = 0;
 | 
						|
 | 
						|
  /// Returns true if this node is a leaf.
 | 
						|
  bool isLeaf() const { return SuffixIdx != EmptyIdx; }
 | 
						|
 | 
						|
  /// Returns true if this node is the root of its owning \p SuffixTree.
 | 
						|
  bool isRoot() const { return StartIdx == EmptyIdx; }
 | 
						|
 | 
						|
  /// Return the number of elements in the substring associated with this node.
 | 
						|
  size_t size() const {
 | 
						|
 | 
						|
    // Is it the root? If so, it's the empty string so return 0.
 | 
						|
    if (isRoot())
 | 
						|
      return 0;
 | 
						|
 | 
						|
    assert(*EndIdx != EmptyIdx && "EndIdx is undefined!");
 | 
						|
 | 
						|
    // Size = the number of elements in the string.
 | 
						|
    // For example, [0 1 2 3] has length 4, not 3. 3-0 = 3, so we have 3-0+1.
 | 
						|
    return *EndIdx - StartIdx + 1;
 | 
						|
  }
 | 
						|
 | 
						|
  SuffixTreeNode(size_t StartIdx, size_t *EndIdx, SuffixTreeNode *Link,
 | 
						|
                 SuffixTreeNode *Parent)
 | 
						|
      : StartIdx(StartIdx), EndIdx(EndIdx), Link(Link), Parent(Parent) {}
 | 
						|
 | 
						|
  SuffixTreeNode() {}
 | 
						|
};
 | 
						|
 | 
						|
/// A data structure for fast substring queries.
 | 
						|
///
 | 
						|
/// Suffix trees represent the suffixes of their input strings in their leaves.
 | 
						|
/// A suffix tree is a type of compressed trie structure where each node
 | 
						|
/// represents an entire substring rather than a single character. Each leaf
 | 
						|
/// of the tree is a suffix.
 | 
						|
///
 | 
						|
/// A suffix tree can be seen as a type of state machine where each state is a
 | 
						|
/// substring of the full string. The tree is structured so that, for a string
 | 
						|
/// of length N, there are exactly N leaves in the tree. This structure allows
 | 
						|
/// us to quickly find repeated substrings of the input string.
 | 
						|
///
 | 
						|
/// In this implementation, a "string" is a vector of unsigned integers.
 | 
						|
/// These integers may result from hashing some data type. A suffix tree can
 | 
						|
/// contain 1 or many strings, which can then be queried as one large string.
 | 
						|
///
 | 
						|
/// The suffix tree is implemented using Ukkonen's algorithm for linear-time
 | 
						|
/// suffix tree construction. Ukkonen's algorithm is explained in more detail
 | 
						|
/// in the paper by Esko Ukkonen "On-line construction of suffix trees. The
 | 
						|
/// paper is available at
 | 
						|
///
 | 
						|
/// https://www.cs.helsinki.fi/u/ukkonen/SuffixT1withFigs.pdf
 | 
						|
class SuffixTree {
 | 
						|
private:
 | 
						|
  /// Each element is an integer representing an instruction in the module.
 | 
						|
  ArrayRef<unsigned> Str;
 | 
						|
 | 
						|
  /// Maintains each node in the tree.
 | 
						|
  SpecificBumpPtrAllocator<SuffixTreeNode> NodeAllocator;
 | 
						|
 | 
						|
  /// The root of the suffix tree.
 | 
						|
  ///
 | 
						|
  /// The root represents the empty string. It is maintained by the
 | 
						|
  /// \p NodeAllocator like every other node in the tree.
 | 
						|
  SuffixTreeNode *Root = nullptr;
 | 
						|
 | 
						|
  /// Stores each leaf node in the tree.
 | 
						|
  ///
 | 
						|
  /// This is used for finding outlining candidates.
 | 
						|
  std::vector<SuffixTreeNode *> LeafVector;
 | 
						|
 | 
						|
  /// Maintains the end indices of the internal nodes in the tree.
 | 
						|
  ///
 | 
						|
  /// Each internal node is guaranteed to never have its end index change
 | 
						|
  /// during the construction algorithm; however, leaves must be updated at
 | 
						|
  /// every step. Therefore, we need to store leaf end indices by reference
 | 
						|
  /// to avoid updating O(N) leaves at every step of construction. Thus,
 | 
						|
  /// every internal node must be allocated its own end index.
 | 
						|
  BumpPtrAllocator InternalEndIdxAllocator;
 | 
						|
 | 
						|
  /// The end index of each leaf in the tree.
 | 
						|
  size_t LeafEndIdx = -1;
 | 
						|
 | 
						|
  /// \brief Helper struct which keeps track of the next insertion point in
 | 
						|
  /// Ukkonen's algorithm.
 | 
						|
  struct ActiveState {
 | 
						|
    /// The next node to insert at.
 | 
						|
    SuffixTreeNode *Node;
 | 
						|
 | 
						|
    /// The index of the first character in the substring currently being added.
 | 
						|
    size_t Idx = EmptyIdx;
 | 
						|
 | 
						|
    /// The length of the substring we have to add at the current step.
 | 
						|
    size_t Len = 0;
 | 
						|
  };
 | 
						|
 | 
						|
  /// \brief The point the next insertion will take place at in the
 | 
						|
  /// construction algorithm.
 | 
						|
  ActiveState Active;
 | 
						|
 | 
						|
  /// Allocate a leaf node and add it to the tree.
 | 
						|
  ///
 | 
						|
  /// \param Parent The parent of this node.
 | 
						|
  /// \param StartIdx The start index of this node's associated string.
 | 
						|
  /// \param Edge The label on the edge leaving \p Parent to this node.
 | 
						|
  ///
 | 
						|
  /// \returns A pointer to the allocated leaf node.
 | 
						|
  SuffixTreeNode *insertLeaf(SuffixTreeNode &Parent, size_t StartIdx,
 | 
						|
                             unsigned Edge) {
 | 
						|
 | 
						|
    assert(StartIdx <= LeafEndIdx && "String can't start after it ends!");
 | 
						|
 | 
						|
    SuffixTreeNode *N = new (NodeAllocator.Allocate()) SuffixTreeNode(StartIdx, 
 | 
						|
                                                                   &LeafEndIdx,
 | 
						|
                                                                       nullptr,
 | 
						|
                                                                      &Parent);
 | 
						|
    Parent.Children[Edge] = N;
 | 
						|
 | 
						|
    return N;
 | 
						|
  }
 | 
						|
 | 
						|
  /// Allocate an internal node and add it to the tree.
 | 
						|
  ///
 | 
						|
  /// \param Parent The parent of this node. Only null when allocating the root.
 | 
						|
  /// \param StartIdx The start index of this node's associated string.
 | 
						|
  /// \param EndIdx The end index of this node's associated string.
 | 
						|
  /// \param Edge The label on the edge leaving \p Parent to this node.
 | 
						|
  ///
 | 
						|
  /// \returns A pointer to the allocated internal node.
 | 
						|
  SuffixTreeNode *insertInternalNode(SuffixTreeNode *Parent, size_t StartIdx,
 | 
						|
                                     size_t EndIdx, unsigned Edge) {
 | 
						|
 | 
						|
    assert(StartIdx <= EndIdx && "String can't start after it ends!");
 | 
						|
    assert(!(!Parent && StartIdx != EmptyIdx) &&
 | 
						|
    "Non-root internal nodes must have parents!");
 | 
						|
 | 
						|
    size_t *E = new (InternalEndIdxAllocator) size_t(EndIdx);
 | 
						|
    SuffixTreeNode *N = new (NodeAllocator.Allocate()) SuffixTreeNode(StartIdx,
 | 
						|
                                                                      E,
 | 
						|
                                                                      Root,
 | 
						|
                                                                      Parent);
 | 
						|
    if (Parent)
 | 
						|
      Parent->Children[Edge] = N;
 | 
						|
 | 
						|
    return N;
 | 
						|
  }
 | 
						|
 | 
						|
  /// \brief Set the suffix indices of the leaves to the start indices of their
 | 
						|
  /// respective suffixes. Also stores each leaf in \p LeafVector at its
 | 
						|
  /// respective suffix index.
 | 
						|
  ///
 | 
						|
  /// \param[in] CurrNode The node currently being visited.
 | 
						|
  /// \param CurrIdx The current index of the string being visited.
 | 
						|
  void setSuffixIndices(SuffixTreeNode &CurrNode, size_t CurrIdx) {
 | 
						|
 | 
						|
    bool IsLeaf = CurrNode.Children.size() == 0 && !CurrNode.isRoot();
 | 
						|
 | 
						|
    // Store the length of the concatenation of all strings from the root to
 | 
						|
    // this node.
 | 
						|
    if (!CurrNode.isRoot()) {
 | 
						|
      if (CurrNode.ConcatLen == 0)
 | 
						|
        CurrNode.ConcatLen = CurrNode.size();
 | 
						|
 | 
						|
      if (CurrNode.Parent)
 | 
						|
       CurrNode.ConcatLen += CurrNode.Parent->ConcatLen;
 | 
						|
    }
 | 
						|
 | 
						|
    // Traverse the tree depth-first.
 | 
						|
    for (auto &ChildPair : CurrNode.Children) {
 | 
						|
      assert(ChildPair.second && "Node had a null child!");
 | 
						|
      setSuffixIndices(*ChildPair.second,
 | 
						|
                       CurrIdx + ChildPair.second->size());
 | 
						|
    }
 | 
						|
 | 
						|
    // Is this node a leaf?
 | 
						|
    if (IsLeaf) {
 | 
						|
      // If yes, give it a suffix index and bump its parent's occurrence count.
 | 
						|
      CurrNode.SuffixIdx = Str.size() - CurrIdx;
 | 
						|
      assert(CurrNode.Parent && "CurrNode had no parent!");
 | 
						|
      CurrNode.Parent->OccurrenceCount++;
 | 
						|
 | 
						|
      // Store the leaf in the leaf vector for pruning later.
 | 
						|
      LeafVector[CurrNode.SuffixIdx] = &CurrNode;
 | 
						|
    }
 | 
						|
  }
 | 
						|
 | 
						|
  /// \brief Construct the suffix tree for the prefix of the input ending at
 | 
						|
  /// \p EndIdx.
 | 
						|
  ///
 | 
						|
  /// Used to construct the full suffix tree iteratively. At the end of each
 | 
						|
  /// step, the constructed suffix tree is either a valid suffix tree, or a
 | 
						|
  /// suffix tree with implicit suffixes. At the end of the final step, the
 | 
						|
  /// suffix tree is a valid tree.
 | 
						|
  ///
 | 
						|
  /// \param EndIdx The end index of the current prefix in the main string.
 | 
						|
  /// \param SuffixesToAdd The number of suffixes that must be added
 | 
						|
  /// to complete the suffix tree at the current phase.
 | 
						|
  ///
 | 
						|
  /// \returns The number of suffixes that have not been added at the end of
 | 
						|
  /// this step.
 | 
						|
  unsigned extend(size_t EndIdx, size_t SuffixesToAdd) {
 | 
						|
    SuffixTreeNode *NeedsLink = nullptr;
 | 
						|
 | 
						|
    while (SuffixesToAdd > 0) {
 | 
						|
    
 | 
						|
      // Are we waiting to add anything other than just the last character?
 | 
						|
      if (Active.Len == 0) {
 | 
						|
        // If not, then say the active index is the end index.
 | 
						|
        Active.Idx = EndIdx;
 | 
						|
      }
 | 
						|
 | 
						|
      assert(Active.Idx <= EndIdx && "Start index can't be after end index!");
 | 
						|
 | 
						|
      // The first character in the current substring we're looking at.
 | 
						|
      unsigned FirstChar = Str[Active.Idx];
 | 
						|
 | 
						|
      // Have we inserted anything starting with FirstChar at the current node?
 | 
						|
      if (Active.Node->Children.count(FirstChar) == 0) {
 | 
						|
        // If not, then we can just insert a leaf and move too the next step.
 | 
						|
        insertLeaf(*Active.Node, EndIdx, FirstChar);
 | 
						|
 | 
						|
        // The active node is an internal node, and we visited it, so it must
 | 
						|
        // need a link if it doesn't have one.
 | 
						|
        if (NeedsLink) {
 | 
						|
          NeedsLink->Link = Active.Node;
 | 
						|
          NeedsLink = nullptr;
 | 
						|
        }
 | 
						|
      } else {
 | 
						|
        // There's a match with FirstChar, so look for the point in the tree to
 | 
						|
        // insert a new node.
 | 
						|
        SuffixTreeNode *NextNode = Active.Node->Children[FirstChar];
 | 
						|
 | 
						|
        size_t SubstringLen = NextNode->size();
 | 
						|
 | 
						|
        // Is the current suffix we're trying to insert longer than the size of
 | 
						|
        // the child we want to move to?
 | 
						|
        if (Active.Len >= SubstringLen) {
 | 
						|
          // If yes, then consume the characters we've seen and move to the next
 | 
						|
          // node.
 | 
						|
          Active.Idx += SubstringLen;
 | 
						|
          Active.Len -= SubstringLen;
 | 
						|
          Active.Node = NextNode;
 | 
						|
          continue;
 | 
						|
        }
 | 
						|
 | 
						|
        // Otherwise, the suffix we're trying to insert must be contained in the
 | 
						|
        // next node we want to move to.
 | 
						|
        unsigned LastChar = Str[EndIdx];
 | 
						|
 | 
						|
        // Is the string we're trying to insert a substring of the next node?
 | 
						|
        if (Str[NextNode->StartIdx + Active.Len] == LastChar) {
 | 
						|
          // If yes, then we're done for this step. Remember our insertion point
 | 
						|
          // and move to the next end index. At this point, we have an implicit
 | 
						|
          // suffix tree.
 | 
						|
          if (NeedsLink && !Active.Node->isRoot()) {
 | 
						|
            NeedsLink->Link = Active.Node;
 | 
						|
            NeedsLink = nullptr;
 | 
						|
          }
 | 
						|
 | 
						|
          Active.Len++;
 | 
						|
          break;
 | 
						|
        }
 | 
						|
 | 
						|
        // The string we're trying to insert isn't a substring of the next node,
 | 
						|
        // but matches up to a point. Split the node.
 | 
						|
        //
 | 
						|
        // For example, say we ended our search at a node n and we're trying to
 | 
						|
        // insert ABD. Then we'll create a new node s for AB, reduce n to just
 | 
						|
        // representing C, and insert a new leaf node l to represent d. This
 | 
						|
        // allows us to ensure that if n was a leaf, it remains a leaf.
 | 
						|
        //
 | 
						|
        //   | ABC  ---split--->  | AB
 | 
						|
        //   n                    s
 | 
						|
        //                     C / \ D
 | 
						|
        //                      n   l
 | 
						|
 | 
						|
        // The node s from the diagram
 | 
						|
        SuffixTreeNode *SplitNode =
 | 
						|
            insertInternalNode(Active.Node,
 | 
						|
                               NextNode->StartIdx,
 | 
						|
                               NextNode->StartIdx + Active.Len - 1,
 | 
						|
                               FirstChar);
 | 
						|
 | 
						|
        // Insert the new node representing the new substring into the tree as
 | 
						|
        // a child of the split node. This is the node l from the diagram.
 | 
						|
        insertLeaf(*SplitNode, EndIdx, LastChar);
 | 
						|
 | 
						|
        // Make the old node a child of the split node and update its start
 | 
						|
        // index. This is the node n from the diagram.
 | 
						|
        NextNode->StartIdx += Active.Len;
 | 
						|
        NextNode->Parent = SplitNode;
 | 
						|
        SplitNode->Children[Str[NextNode->StartIdx]] = NextNode;
 | 
						|
 | 
						|
        // SplitNode is an internal node, update the suffix link.
 | 
						|
        if (NeedsLink)
 | 
						|
          NeedsLink->Link = SplitNode;
 | 
						|
 | 
						|
        NeedsLink = SplitNode;
 | 
						|
      }
 | 
						|
 | 
						|
      // We've added something new to the tree, so there's one less suffix to
 | 
						|
      // add.
 | 
						|
      SuffixesToAdd--;
 | 
						|
 | 
						|
      if (Active.Node->isRoot()) {
 | 
						|
        if (Active.Len > 0) {
 | 
						|
          Active.Len--;
 | 
						|
          Active.Idx = EndIdx - SuffixesToAdd + 1;
 | 
						|
        }
 | 
						|
      } else {
 | 
						|
        // Start the next phase at the next smallest suffix.
 | 
						|
        Active.Node = Active.Node->Link;
 | 
						|
      }
 | 
						|
    }
 | 
						|
 | 
						|
    return SuffixesToAdd;
 | 
						|
  }
 | 
						|
 | 
						|
public:
 | 
						|
 | 
						|
  /// Find all repeated substrings that satisfy \p BenefitFn.
 | 
						|
  ///
 | 
						|
  /// If a substring appears at least twice, then it must be represented by
 | 
						|
  /// an internal node which appears in at least two suffixes. Each suffix is
 | 
						|
  /// represented by a leaf node. To do this, we visit each internal node in
 | 
						|
  /// the tree, using the leaf children of each internal node. If an internal
 | 
						|
  /// node represents a beneficial substring, then we use each of its leaf
 | 
						|
  /// children to find the locations of its substring.
 | 
						|
  ///
 | 
						|
  /// \param[out] CandidateList Filled with candidates representing each
 | 
						|
  /// beneficial substring.
 | 
						|
  /// \param[out] FunctionList Filled with a list of \p OutlinedFunctions each
 | 
						|
  /// type of candidate.
 | 
						|
  /// \param BenefitFn The function to satisfy.
 | 
						|
  ///
 | 
						|
  /// \returns The length of the longest candidate found.
 | 
						|
  size_t findCandidates(std::vector<Candidate> &CandidateList,
 | 
						|
  std::vector<OutlinedFunction> &FunctionList,
 | 
						|
  const std::function<unsigned(SuffixTreeNode &, size_t, unsigned)>
 | 
						|
  &BenefitFn) {
 | 
						|
 | 
						|
    CandidateList.clear();
 | 
						|
    FunctionList.clear();
 | 
						|
    size_t FnIdx = 0;
 | 
						|
    size_t MaxLen = 0;
 | 
						|
 | 
						|
    for (SuffixTreeNode* Leaf : LeafVector) {
 | 
						|
      assert(Leaf && "Leaves in LeafVector cannot be null!");
 | 
						|
      if (!Leaf->IsInTree)
 | 
						|
        continue;
 | 
						|
 | 
						|
      assert(Leaf->Parent && "All leaves must have parents!");
 | 
						|
      SuffixTreeNode &Parent = *(Leaf->Parent);
 | 
						|
 | 
						|
      // If it doesn't appear enough, or we already outlined from it, skip it.
 | 
						|
      if (Parent.OccurrenceCount < 2 || Parent.isRoot() || !Parent.IsInTree)
 | 
						|
        continue;
 | 
						|
 | 
						|
      size_t StringLen = Leaf->ConcatLen - Leaf->size();
 | 
						|
 | 
						|
      // How many instructions would outlining this string save?
 | 
						|
      unsigned Benefit = BenefitFn(Parent,
 | 
						|
        StringLen, Str[Leaf->SuffixIdx + StringLen - 1]);
 | 
						|
 | 
						|
      // If it's not beneficial, skip it.
 | 
						|
      if (Benefit < 1)
 | 
						|
        continue;
 | 
						|
 | 
						|
      if (StringLen > MaxLen)
 | 
						|
        MaxLen = StringLen;
 | 
						|
 | 
						|
      unsigned OccurrenceCount = 0;
 | 
						|
      for (auto &ChildPair : Parent.Children) {
 | 
						|
        SuffixTreeNode *M = ChildPair.second;
 | 
						|
 | 
						|
        // Is it a leaf? If so, we have an occurrence of this candidate.
 | 
						|
        if (M && M->IsInTree && M->isLeaf()) {
 | 
						|
          OccurrenceCount++;
 | 
						|
          CandidateList.emplace_back(M->SuffixIdx, StringLen, FnIdx);
 | 
						|
          CandidateList.back().Benefit = Benefit;
 | 
						|
          M->IsInTree = false;
 | 
						|
        }
 | 
						|
      }
 | 
						|
 | 
						|
      // Save the function for the new candidate sequence.
 | 
						|
      std::vector<unsigned> CandidateSequence;
 | 
						|
      for (unsigned i = Leaf->SuffixIdx; i < Leaf->SuffixIdx + StringLen; i++)
 | 
						|
        CandidateSequence.push_back(Str[i]);
 | 
						|
 | 
						|
      FunctionList.emplace_back(FnIdx, OccurrenceCount, CandidateSequence,
 | 
						|
                                Benefit, false);
 | 
						|
 | 
						|
      // Move to the next function.
 | 
						|
      FnIdx++;
 | 
						|
      Parent.IsInTree = false;
 | 
						|
    }
 | 
						|
 | 
						|
    return MaxLen;
 | 
						|
  }
 | 
						|
 
 | 
						|
  /// Construct a suffix tree from a sequence of unsigned integers.
 | 
						|
  ///
 | 
						|
  /// \param Str The string to construct the suffix tree for.
 | 
						|
  SuffixTree(const std::vector<unsigned> &Str) : Str(Str) {
 | 
						|
    Root = insertInternalNode(nullptr, EmptyIdx, EmptyIdx, 0);
 | 
						|
    Root->IsInTree = true;
 | 
						|
    Active.Node = Root;
 | 
						|
    LeafVector = std::vector<SuffixTreeNode*>(Str.size());
 | 
						|
 | 
						|
    // Keep track of the number of suffixes we have to add of the current
 | 
						|
    // prefix.
 | 
						|
    size_t SuffixesToAdd = 0;
 | 
						|
    Active.Node = Root;
 | 
						|
 | 
						|
    // Construct the suffix tree iteratively on each prefix of the string.
 | 
						|
    // PfxEndIdx is the end index of the current prefix.
 | 
						|
    // End is one past the last element in the string.
 | 
						|
    for (size_t PfxEndIdx = 0, End = Str.size(); PfxEndIdx < End; PfxEndIdx++) {
 | 
						|
      SuffixesToAdd++;
 | 
						|
      LeafEndIdx = PfxEndIdx; // Extend each of the leaves.
 | 
						|
      SuffixesToAdd = extend(PfxEndIdx, SuffixesToAdd);
 | 
						|
    }
 | 
						|
 | 
						|
    // Set the suffix indices of each leaf.
 | 
						|
    assert(Root && "Root node can't be nullptr!");
 | 
						|
    setSuffixIndices(*Root, 0);
 | 
						|
  }
 | 
						|
};
 | 
						|
 | 
						|
/// \brief Maps \p MachineInstrs to unsigned integers and stores the mappings.
 | 
						|
struct InstructionMapper {
 | 
						|
 | 
						|
  /// \brief The next available integer to assign to a \p MachineInstr that
 | 
						|
  /// cannot be outlined.
 | 
						|
  ///
 | 
						|
  /// Set to -3 for compatability with \p DenseMapInfo<unsigned>.
 | 
						|
  unsigned IllegalInstrNumber = -3;
 | 
						|
 | 
						|
  /// \brief The next available integer to assign to a \p MachineInstr that can
 | 
						|
  /// be outlined.
 | 
						|
  unsigned LegalInstrNumber = 0;
 | 
						|
 | 
						|
  /// Correspondence from \p MachineInstrs to unsigned integers.
 | 
						|
  DenseMap<MachineInstr *, unsigned, MachineInstrExpressionTrait>
 | 
						|
      InstructionIntegerMap;
 | 
						|
 | 
						|
  /// Corresponcence from unsigned integers to \p MachineInstrs.
 | 
						|
  /// Inverse of \p InstructionIntegerMap.
 | 
						|
  DenseMap<unsigned, MachineInstr *> IntegerInstructionMap;
 | 
						|
 | 
						|
  /// The vector of unsigned integers that the module is mapped to.
 | 
						|
  std::vector<unsigned> UnsignedVec;
 | 
						|
 | 
						|
  /// \brief Stores the location of the instruction associated with the integer
 | 
						|
  /// at index i in \p UnsignedVec for each index i.
 | 
						|
  std::vector<MachineBasicBlock::iterator> InstrList;
 | 
						|
 | 
						|
  /// \brief Maps \p *It to a legal integer.
 | 
						|
  ///
 | 
						|
  /// Updates \p InstrList, \p UnsignedVec, \p InstructionIntegerMap,
 | 
						|
  /// \p IntegerInstructionMap, and \p LegalInstrNumber.
 | 
						|
  ///
 | 
						|
  /// \returns The integer that \p *It was mapped to.
 | 
						|
  unsigned mapToLegalUnsigned(MachineBasicBlock::iterator &It) {
 | 
						|
 | 
						|
    // Get the integer for this instruction or give it the current
 | 
						|
    // LegalInstrNumber.
 | 
						|
    InstrList.push_back(It);
 | 
						|
    MachineInstr &MI = *It;
 | 
						|
    bool WasInserted;
 | 
						|
    DenseMap<MachineInstr *, unsigned, MachineInstrExpressionTrait>::iterator
 | 
						|
    ResultIt;
 | 
						|
    std::tie(ResultIt, WasInserted) =
 | 
						|
    InstructionIntegerMap.insert(std::make_pair(&MI, LegalInstrNumber));
 | 
						|
    unsigned MINumber = ResultIt->second;
 | 
						|
 | 
						|
    // There was an insertion.
 | 
						|
    if (WasInserted) {
 | 
						|
      LegalInstrNumber++;
 | 
						|
      IntegerInstructionMap.insert(std::make_pair(MINumber, &MI));
 | 
						|
    }
 | 
						|
 | 
						|
    UnsignedVec.push_back(MINumber);
 | 
						|
 | 
						|
    // Make sure we don't overflow or use any integers reserved by the DenseMap.
 | 
						|
    if (LegalInstrNumber >= IllegalInstrNumber)
 | 
						|
      report_fatal_error("Instruction mapping overflow!");
 | 
						|
 | 
						|
    assert(LegalInstrNumber != DenseMapInfo<unsigned>::getEmptyKey()
 | 
						|
          && "Tried to assign DenseMap tombstone or empty key to instruction.");
 | 
						|
    assert(LegalInstrNumber != DenseMapInfo<unsigned>::getTombstoneKey()
 | 
						|
          && "Tried to assign DenseMap tombstone or empty key to instruction.");
 | 
						|
 | 
						|
    return MINumber;
 | 
						|
  }
 | 
						|
 | 
						|
  /// Maps \p *It to an illegal integer.
 | 
						|
  ///
 | 
						|
  /// Updates \p InstrList, \p UnsignedVec, and \p IllegalInstrNumber.
 | 
						|
  ///
 | 
						|
  /// \returns The integer that \p *It was mapped to.
 | 
						|
  unsigned mapToIllegalUnsigned(MachineBasicBlock::iterator &It) {
 | 
						|
    unsigned MINumber = IllegalInstrNumber;
 | 
						|
 | 
						|
    InstrList.push_back(It);
 | 
						|
    UnsignedVec.push_back(IllegalInstrNumber);
 | 
						|
    IllegalInstrNumber--;
 | 
						|
 | 
						|
    assert(LegalInstrNumber < IllegalInstrNumber &&
 | 
						|
           "Instruction mapping overflow!");
 | 
						|
 | 
						|
    assert(IllegalInstrNumber !=
 | 
						|
      DenseMapInfo<unsigned>::getEmptyKey() &&
 | 
						|
      "IllegalInstrNumber cannot be DenseMap tombstone or empty key!");
 | 
						|
 | 
						|
    assert(IllegalInstrNumber !=
 | 
						|
      DenseMapInfo<unsigned>::getTombstoneKey() &&
 | 
						|
      "IllegalInstrNumber cannot be DenseMap tombstone or empty key!");
 | 
						|
 | 
						|
    return MINumber;
 | 
						|
  }
 | 
						|
 | 
						|
  /// \brief Transforms a \p MachineBasicBlock into a \p vector of \p unsigneds
 | 
						|
  /// and appends it to \p UnsignedVec and \p InstrList.
 | 
						|
  ///
 | 
						|
  /// Two instructions are assigned the same integer if they are identical.
 | 
						|
  /// If an instruction is deemed unsafe to outline, then it will be assigned an
 | 
						|
  /// unique integer. The resulting mapping is placed into a suffix tree and
 | 
						|
  /// queried for candidates.
 | 
						|
  ///
 | 
						|
  /// \param MBB The \p MachineBasicBlock to be translated into integers.
 | 
						|
  /// \param TRI \p TargetRegisterInfo for the module.
 | 
						|
  /// \param TII \p TargetInstrInfo for the module.
 | 
						|
  void convertToUnsignedVec(MachineBasicBlock &MBB,
 | 
						|
                            const TargetRegisterInfo &TRI,
 | 
						|
                            const TargetInstrInfo &TII) {
 | 
						|
    for (MachineBasicBlock::iterator It = MBB.begin(), Et = MBB.end(); It != Et;
 | 
						|
         It++) {
 | 
						|
 | 
						|
      // Keep track of where this instruction is in the module.
 | 
						|
      switch(TII.getOutliningType(*It)) {
 | 
						|
        case TargetInstrInfo::MachineOutlinerInstrType::Illegal:
 | 
						|
          mapToIllegalUnsigned(It);
 | 
						|
          break;
 | 
						|
 | 
						|
        case TargetInstrInfo::MachineOutlinerInstrType::Legal:
 | 
						|
          mapToLegalUnsigned(It);
 | 
						|
          break;
 | 
						|
 | 
						|
        case TargetInstrInfo::MachineOutlinerInstrType::Invisible:
 | 
						|
          break;
 | 
						|
      }
 | 
						|
    }
 | 
						|
 | 
						|
    // After we're done every insertion, uniquely terminate this part of the
 | 
						|
    // "string". This makes sure we won't match across basic block or function
 | 
						|
    // boundaries since the "end" is encoded uniquely and thus appears in no
 | 
						|
    // repeated substring.
 | 
						|
    InstrList.push_back(MBB.end());
 | 
						|
    UnsignedVec.push_back(IllegalInstrNumber);
 | 
						|
    IllegalInstrNumber--;
 | 
						|
  }
 | 
						|
 | 
						|
  InstructionMapper() {
 | 
						|
    // Make sure that the implementation of DenseMapInfo<unsigned> hasn't
 | 
						|
    // changed.
 | 
						|
    assert(DenseMapInfo<unsigned>::getEmptyKey() == (unsigned)-1 &&
 | 
						|
                "DenseMapInfo<unsigned>'s empty key isn't -1!");
 | 
						|
    assert(DenseMapInfo<unsigned>::getTombstoneKey() == (unsigned)-2 &&
 | 
						|
                "DenseMapInfo<unsigned>'s tombstone key isn't -2!");
 | 
						|
  }
 | 
						|
};
 | 
						|
 | 
						|
/// \brief An interprocedural pass which finds repeated sequences of
 | 
						|
/// instructions and replaces them with calls to functions.
 | 
						|
///
 | 
						|
/// Each instruction is mapped to an unsigned integer and placed in a string.
 | 
						|
/// The resulting mapping is then placed in a \p SuffixTree. The \p SuffixTree
 | 
						|
/// is then repeatedly queried for repeated sequences of instructions. Each
 | 
						|
/// non-overlapping repeated sequence is then placed in its own
 | 
						|
/// \p MachineFunction and each instance is then replaced with a call to that
 | 
						|
/// function.
 | 
						|
struct MachineOutliner : public ModulePass {
 | 
						|
 | 
						|
  static char ID;
 | 
						|
 | 
						|
  StringRef getPassName() const override { return "Machine Outliner"; }
 | 
						|
 | 
						|
  void getAnalysisUsage(AnalysisUsage &AU) const override {
 | 
						|
    AU.addRequired<MachineModuleInfo>();
 | 
						|
    AU.addPreserved<MachineModuleInfo>();
 | 
						|
    AU.setPreservesAll();
 | 
						|
    ModulePass::getAnalysisUsage(AU);
 | 
						|
  }
 | 
						|
 | 
						|
  MachineOutliner() : ModulePass(ID) {
 | 
						|
    initializeMachineOutlinerPass(*PassRegistry::getPassRegistry());
 | 
						|
  }
 | 
						|
 | 
						|
  /// \brief Replace the sequences of instructions represented by the
 | 
						|
  /// \p Candidates in \p CandidateList with calls to \p MachineFunctions
 | 
						|
  /// described in \p FunctionList.
 | 
						|
  ///
 | 
						|
  /// \param M The module we are outlining from.
 | 
						|
  /// \param CandidateList A list of candidates to be outlined.
 | 
						|
  /// \param FunctionList A list of functions to be inserted into the module.
 | 
						|
  /// \param Mapper Contains the instruction mappings for the module.
 | 
						|
  bool outline(Module &M, const ArrayRef<Candidate> &CandidateList,
 | 
						|
               std::vector<OutlinedFunction> &FunctionList,
 | 
						|
               InstructionMapper &Mapper);
 | 
						|
 | 
						|
  /// Creates a function for \p OF and inserts it into the module.
 | 
						|
  MachineFunction *createOutlinedFunction(Module &M, const OutlinedFunction &OF,
 | 
						|
                                          InstructionMapper &Mapper);
 | 
						|
 | 
						|
  /// Find potential outlining candidates and store them in \p CandidateList.
 | 
						|
  ///
 | 
						|
  /// For each type of potential candidate, also build an \p OutlinedFunction
 | 
						|
  /// struct containing the information to build the function for that
 | 
						|
  /// candidate.
 | 
						|
  ///
 | 
						|
  /// \param[out] CandidateList Filled with outlining candidates for the module.
 | 
						|
  /// \param[out] FunctionList Filled with functions corresponding to each type
 | 
						|
  /// of \p Candidate.
 | 
						|
  /// \param ST The suffix tree for the module.
 | 
						|
  /// \param TII TargetInstrInfo for the module.
 | 
						|
  ///
 | 
						|
  /// \returns The length of the longest candidate found. 0 if there are none.
 | 
						|
  unsigned buildCandidateList(std::vector<Candidate> &CandidateList,
 | 
						|
                              std::vector<OutlinedFunction> &FunctionList,
 | 
						|
                              SuffixTree &ST,
 | 
						|
                              InstructionMapper &Mapper,
 | 
						|
                              const TargetInstrInfo &TII);
 | 
						|
 | 
						|
  /// \brief Remove any overlapping candidates that weren't handled by the
 | 
						|
  /// suffix tree's pruning method.
 | 
						|
  ///
 | 
						|
  /// Pruning from the suffix tree doesn't necessarily remove all overlaps.
 | 
						|
  /// If a short candidate is chosen for outlining, then a longer candidate
 | 
						|
  /// which has that short candidate as a suffix is chosen, the tree's pruning
 | 
						|
  /// method will not find it. Thus, we need to prune before outlining as well.
 | 
						|
  ///
 | 
						|
  /// \param[in,out] CandidateList A list of outlining candidates.
 | 
						|
  /// \param[in,out] FunctionList A list of functions to be outlined.
 | 
						|
  /// \param MaxCandidateLen The length of the longest candidate.
 | 
						|
  /// \param TII TargetInstrInfo for the module.
 | 
						|
  void pruneOverlaps(std::vector<Candidate> &CandidateList,
 | 
						|
                     std::vector<OutlinedFunction> &FunctionList,
 | 
						|
                     unsigned MaxCandidateLen,
 | 
						|
                     const TargetInstrInfo &TII);
 | 
						|
 | 
						|
  /// Construct a suffix tree on the instructions in \p M and outline repeated
 | 
						|
  /// strings from that tree.
 | 
						|
  bool runOnModule(Module &M) override;
 | 
						|
};
 | 
						|
 | 
						|
} // Anonymous namespace.
 | 
						|
 | 
						|
char MachineOutliner::ID = 0;
 | 
						|
 | 
						|
namespace llvm {
 | 
						|
ModulePass *createMachineOutlinerPass() { return new MachineOutliner(); }
 | 
						|
}
 | 
						|
 | 
						|
INITIALIZE_PASS(MachineOutliner, "machine-outliner",
 | 
						|
                "Machine Function Outliner", false, false)
 | 
						|
 | 
						|
void MachineOutliner::pruneOverlaps(std::vector<Candidate> &CandidateList,
 | 
						|
                                    std::vector<OutlinedFunction> &FunctionList,
 | 
						|
                                    unsigned MaxCandidateLen,
 | 
						|
                                    const TargetInstrInfo &TII) {
 | 
						|
  // TODO: Experiment with interval trees or other interval-checking structures
 | 
						|
  // to lower the time complexity of this function.
 | 
						|
  // TODO: Can we do better than the simple greedy choice?
 | 
						|
  // Check for overlaps in the range.
 | 
						|
  // This is O(MaxCandidateLen * CandidateList.size()).
 | 
						|
  for (auto It = CandidateList.begin(), Et = CandidateList.end(); It != Et;
 | 
						|
       It++) {
 | 
						|
    Candidate &C1 = *It;
 | 
						|
    OutlinedFunction &F1 = FunctionList[C1.FunctionIdx];
 | 
						|
 | 
						|
    // If we removed this candidate, skip it.
 | 
						|
    if (!C1.InCandidateList)
 | 
						|
      continue;
 | 
						|
 | 
						|
    // Is it still worth it to outline C1?
 | 
						|
    if (F1.Benefit < 1 || F1.OccurrenceCount < 2) {
 | 
						|
      assert(F1.OccurrenceCount > 0 &&
 | 
						|
               "Can't remove OutlinedFunction with no occurrences!");
 | 
						|
      F1.OccurrenceCount--;
 | 
						|
      C1.InCandidateList = false;
 | 
						|
      continue;
 | 
						|
    }
 | 
						|
 | 
						|
    // The minimum start index of any candidate that could overlap with this
 | 
						|
    // one.
 | 
						|
    unsigned FarthestPossibleIdx = 0;
 | 
						|
 | 
						|
    // Either the index is 0, or it's at most MaxCandidateLen indices away.
 | 
						|
    if (C1.StartIdx > MaxCandidateLen)
 | 
						|
      FarthestPossibleIdx = C1.StartIdx - MaxCandidateLen;
 | 
						|
 | 
						|
    // Compare against the candidates in the list that start at at most
 | 
						|
    // FarthestPossibleIdx indices away from C1. There are at most
 | 
						|
    // MaxCandidateLen of these.
 | 
						|
    for (auto Sit = It + 1; Sit != Et; Sit++) {
 | 
						|
      Candidate &C2 = *Sit;
 | 
						|
      OutlinedFunction &F2 = FunctionList[C2.FunctionIdx];
 | 
						|
 | 
						|
      // Is this candidate too far away to overlap?
 | 
						|
      if (C2.StartIdx < FarthestPossibleIdx)
 | 
						|
        break;
 | 
						|
 | 
						|
      // Did we already remove this candidate in a previous step?
 | 
						|
      if (!C2.InCandidateList)
 | 
						|
        continue;
 | 
						|
 | 
						|
      // Is the function beneficial to outline?
 | 
						|
      if (F2.OccurrenceCount < 2 || F2.Benefit < 1) {
 | 
						|
        // If not, remove this candidate and move to the next one.
 | 
						|
        assert(F2.OccurrenceCount > 0 &&
 | 
						|
               "Can't remove OutlinedFunction with no occurrences!");
 | 
						|
        F2.OccurrenceCount--;
 | 
						|
        C2.InCandidateList = false;
 | 
						|
        continue;
 | 
						|
      }
 | 
						|
 | 
						|
      size_t C2End = C2.StartIdx + C2.Len - 1;
 | 
						|
 | 
						|
      // Do C1 and C2 overlap?
 | 
						|
      //
 | 
						|
      // Not overlapping:
 | 
						|
      // High indices... [C1End ... C1Start][C2End ... C2Start] ...Low indices
 | 
						|
      //
 | 
						|
      // We sorted our candidate list so C2Start <= C1Start. We know that
 | 
						|
      // C2End > C2Start since each candidate has length >= 2. Therefore, all we
 | 
						|
      // have to check is C2End < C2Start to see if we overlap.
 | 
						|
      if (C2End < C1.StartIdx)
 | 
						|
        continue;
 | 
						|
 | 
						|
      // C1 and C2 overlap.
 | 
						|
      // We need to choose the better of the two.
 | 
						|
      //
 | 
						|
      // Approximate this by picking the one which would have saved us the
 | 
						|
      // most instructions before any pruning.
 | 
						|
      if (C1.Benefit >= C2.Benefit) {
 | 
						|
 | 
						|
        // C1 is better, so remove C2 and update C2's OutlinedFunction to
 | 
						|
        // reflect the removal.
 | 
						|
        assert(F2.OccurrenceCount > 0 &&
 | 
						|
               "Can't remove OutlinedFunction with no occurrences!");
 | 
						|
        F2.OccurrenceCount--;
 | 
						|
        F2.Benefit = TII.getOutliningBenefit(F2.Sequence.size(),
 | 
						|
                                             F2.OccurrenceCount,
 | 
						|
                                             F2.IsTailCall
 | 
						|
                                             );
 | 
						|
 | 
						|
        C2.InCandidateList = false;
 | 
						|
 | 
						|
        DEBUG (
 | 
						|
          dbgs() << "- Removed C2. \n";
 | 
						|
          dbgs() << "--- Num fns left for C2: " << F2.OccurrenceCount << "\n";
 | 
						|
          dbgs() << "--- C2's benefit: " << F2.Benefit << "\n";
 | 
						|
        );
 | 
						|
 | 
						|
      } else {
 | 
						|
        // C2 is better, so remove C1 and update C1's OutlinedFunction to
 | 
						|
        // reflect the removal.
 | 
						|
        assert(F1.OccurrenceCount > 0 &&
 | 
						|
               "Can't remove OutlinedFunction with no occurrences!");
 | 
						|
        F1.OccurrenceCount--;
 | 
						|
        F1.Benefit = TII.getOutliningBenefit(F1.Sequence.size(),
 | 
						|
                                             F1.OccurrenceCount,
 | 
						|
                                             F1.IsTailCall
 | 
						|
                                             );
 | 
						|
        C1.InCandidateList = false;
 | 
						|
 | 
						|
        DEBUG (
 | 
						|
          dbgs() << "- Removed C1. \n";
 | 
						|
          dbgs() << "--- Num fns left for C1: " << F1.OccurrenceCount << "\n";
 | 
						|
          dbgs() << "--- C1's benefit: " << F1.Benefit << "\n";
 | 
						|
        );
 | 
						|
 | 
						|
        // C1 is out, so we don't have to compare it against anyone else.
 | 
						|
        break;
 | 
						|
      }
 | 
						|
    }
 | 
						|
  }
 | 
						|
}
 | 
						|
 | 
						|
unsigned
 | 
						|
MachineOutliner::buildCandidateList(std::vector<Candidate> &CandidateList,
 | 
						|
                                    std::vector<OutlinedFunction> &FunctionList,
 | 
						|
                                    SuffixTree &ST,
 | 
						|
                                    InstructionMapper &Mapper,
 | 
						|
                                    const TargetInstrInfo &TII) {
 | 
						|
 | 
						|
  std::vector<unsigned> CandidateSequence; // Current outlining candidate.
 | 
						|
  size_t MaxCandidateLen = 0; // Length of the longest candidate.
 | 
						|
 | 
						|
  // Function for maximizing query in the suffix tree.
 | 
						|
  // This allows us to define more fine-grained types of things to outline in
 | 
						|
  // the target without putting target-specific info in the suffix tree.
 | 
						|
  auto BenefitFn = [&TII, &Mapper](const SuffixTreeNode &Curr,
 | 
						|
                                   size_t StringLen, unsigned EndVal) {
 | 
						|
 | 
						|
    // The root represents the empty string.
 | 
						|
    if (Curr.isRoot())
 | 
						|
      return 0u;
 | 
						|
 | 
						|
    // Is this long enough to outline?
 | 
						|
	// TODO: Let the target decide how "long" a string is in terms of the sizes
 | 
						|
	// of the instructions in the string. For example, if a call instruction
 | 
						|
	// is smaller than a one instruction string, we should outline that string.
 | 
						|
    if (StringLen < 2)
 | 
						|
      return 0u;
 | 
						|
 | 
						|
    size_t Occurrences = Curr.OccurrenceCount;
 | 
						|
 | 
						|
    // Anything we want to outline has to appear at least twice.
 | 
						|
    if (Occurrences < 2)
 | 
						|
      return 0u;
 | 
						|
 | 
						|
    // Check if the last instruction in the sequence is a return.
 | 
						|
    MachineInstr *LastInstr =
 | 
						|
    Mapper.IntegerInstructionMap[EndVal];
 | 
						|
    assert(LastInstr && "Last instruction in sequence was unmapped!");
 | 
						|
 | 
						|
    // The only way a terminator could be mapped as legal is if it was safe to
 | 
						|
    // tail call.
 | 
						|
    bool IsTailCall = LastInstr->isTerminator();
 | 
						|
    return TII.getOutliningBenefit(StringLen, Occurrences, IsTailCall);
 | 
						|
  };
 | 
						|
 | 
						|
  MaxCandidateLen = ST.findCandidates(CandidateList, FunctionList, BenefitFn);
 | 
						|
 | 
						|
  for (auto &OF : FunctionList)
 | 
						|
    OF.IsTailCall = Mapper.
 | 
						|
                    IntegerInstructionMap[OF.Sequence.back()]->isTerminator();
 | 
						|
 | 
						|
  // Sort the candidates in decending order. This will simplify the outlining
 | 
						|
  // process when we have to remove the candidates from the mapping by
 | 
						|
  // allowing us to cut them out without keeping track of an offset.
 | 
						|
  std::stable_sort(CandidateList.begin(), CandidateList.end());
 | 
						|
 | 
						|
  return MaxCandidateLen;
 | 
						|
}
 | 
						|
 | 
						|
MachineFunction *
 | 
						|
MachineOutliner::createOutlinedFunction(Module &M, const OutlinedFunction &OF,
 | 
						|
  InstructionMapper &Mapper) {
 | 
						|
 | 
						|
  // Create the function name. This should be unique. For now, just hash the
 | 
						|
  // module name and include it in the function name plus the number of this
 | 
						|
  // function.
 | 
						|
  std::ostringstream NameStream;
 | 
						|
  NameStream << "OUTLINED_FUNCTION" << "_" << OF.Name;
 | 
						|
 | 
						|
  // Create the function using an IR-level function.
 | 
						|
  LLVMContext &C = M.getContext();
 | 
						|
  Function *F = dyn_cast<Function>(
 | 
						|
      M.getOrInsertFunction(NameStream.str(), Type::getVoidTy(C)));
 | 
						|
  assert(F && "Function was null!");
 | 
						|
 | 
						|
  // NOTE: If this is linkonceodr, then we can take advantage of linker deduping
 | 
						|
  // which gives us better results when we outline from linkonceodr functions.
 | 
						|
  F->setLinkage(GlobalValue::PrivateLinkage);
 | 
						|
  F->setUnnamedAddr(GlobalValue::UnnamedAddr::Global);
 | 
						|
 | 
						|
  BasicBlock *EntryBB = BasicBlock::Create(C, "entry", F);
 | 
						|
  IRBuilder<> Builder(EntryBB);
 | 
						|
  Builder.CreateRetVoid();
 | 
						|
 | 
						|
  MachineModuleInfo &MMI = getAnalysis<MachineModuleInfo>();
 | 
						|
  MachineFunction &MF = MMI.getMachineFunction(*F);
 | 
						|
  MachineBasicBlock &MBB = *MF.CreateMachineBasicBlock();
 | 
						|
  const TargetSubtargetInfo &STI = MF.getSubtarget();
 | 
						|
  const TargetInstrInfo &TII = *STI.getInstrInfo();
 | 
						|
 | 
						|
  // Insert the new function into the module.
 | 
						|
  MF.insert(MF.begin(), &MBB);
 | 
						|
 | 
						|
  TII.insertOutlinerPrologue(MBB, MF, OF.IsTailCall);
 | 
						|
 | 
						|
  // Copy over the instructions for the function using the integer mappings in
 | 
						|
  // its sequence.
 | 
						|
  for (unsigned Str : OF.Sequence) {
 | 
						|
    MachineInstr *NewMI =
 | 
						|
        MF.CloneMachineInstr(Mapper.IntegerInstructionMap.find(Str)->second);
 | 
						|
    NewMI->dropMemRefs();
 | 
						|
 | 
						|
    // Don't keep debug information for outlined instructions.
 | 
						|
    // FIXME: This means outlined functions are currently undebuggable.
 | 
						|
    NewMI->setDebugLoc(DebugLoc());
 | 
						|
    MBB.insert(MBB.end(), NewMI);
 | 
						|
  }
 | 
						|
 | 
						|
  TII.insertOutlinerEpilogue(MBB, MF, OF.IsTailCall);
 | 
						|
 | 
						|
  return &MF;
 | 
						|
}
 | 
						|
 | 
						|
bool MachineOutliner::outline(Module &M,
 | 
						|
                              const ArrayRef<Candidate> &CandidateList,
 | 
						|
                              std::vector<OutlinedFunction> &FunctionList,
 | 
						|
                              InstructionMapper &Mapper) {
 | 
						|
 | 
						|
  bool OutlinedSomething = false;
 | 
						|
 | 
						|
  // Replace the candidates with calls to their respective outlined functions.
 | 
						|
  for (const Candidate &C : CandidateList) {
 | 
						|
 | 
						|
    // Was the candidate removed during pruneOverlaps?
 | 
						|
    if (!C.InCandidateList)
 | 
						|
      continue;
 | 
						|
 | 
						|
    // If not, then look at its OutlinedFunction.
 | 
						|
    OutlinedFunction &OF = FunctionList[C.FunctionIdx];
 | 
						|
 | 
						|
    // Was its OutlinedFunction made unbeneficial during pruneOverlaps?
 | 
						|
    if (OF.OccurrenceCount < 2 || OF.Benefit < 1)
 | 
						|
      continue;
 | 
						|
 | 
						|
    // If not, then outline it.
 | 
						|
    assert(C.StartIdx < Mapper.InstrList.size() && "Candidate out of bounds!");
 | 
						|
    MachineBasicBlock *MBB = (*Mapper.InstrList[C.StartIdx]).getParent();
 | 
						|
    MachineBasicBlock::iterator StartIt = Mapper.InstrList[C.StartIdx];
 | 
						|
    unsigned EndIdx = C.StartIdx + C.Len - 1;
 | 
						|
 | 
						|
    assert(EndIdx < Mapper.InstrList.size() && "Candidate out of bounds!");
 | 
						|
    MachineBasicBlock::iterator EndIt = Mapper.InstrList[EndIdx];
 | 
						|
    assert(EndIt != MBB->end() && "EndIt out of bounds!");
 | 
						|
 | 
						|
    EndIt++; // Erase needs one past the end index.
 | 
						|
 | 
						|
    // Does this candidate have a function yet?
 | 
						|
    if (!OF.MF) {
 | 
						|
      OF.MF = createOutlinedFunction(M, OF, Mapper);
 | 
						|
      FunctionsCreated++;
 | 
						|
    }
 | 
						|
 | 
						|
    MachineFunction *MF = OF.MF;
 | 
						|
    const TargetSubtargetInfo &STI = MF->getSubtarget();
 | 
						|
    const TargetInstrInfo &TII = *STI.getInstrInfo();
 | 
						|
 | 
						|
    // Insert a call to the new function and erase the old sequence.
 | 
						|
    TII.insertOutlinedCall(M, *MBB, StartIt, *MF, OF.IsTailCall);
 | 
						|
    StartIt = Mapper.InstrList[C.StartIdx];
 | 
						|
    MBB->erase(StartIt, EndIt);
 | 
						|
 | 
						|
    OutlinedSomething = true;
 | 
						|
 | 
						|
    // Statistics.
 | 
						|
    NumOutlined++;
 | 
						|
  }
 | 
						|
 | 
						|
  DEBUG (
 | 
						|
    dbgs() << "OutlinedSomething = " << OutlinedSomething << "\n";
 | 
						|
  );
 | 
						|
 | 
						|
  return OutlinedSomething;
 | 
						|
}
 | 
						|
 | 
						|
bool MachineOutliner::runOnModule(Module &M) {
 | 
						|
 | 
						|
  // Is there anything in the module at all?
 | 
						|
  if (M.empty())
 | 
						|
    return false;
 | 
						|
 | 
						|
  MachineModuleInfo &MMI = getAnalysis<MachineModuleInfo>();
 | 
						|
  const TargetSubtargetInfo &STI = MMI.getMachineFunction(*M.begin())
 | 
						|
                                      .getSubtarget();
 | 
						|
  const TargetRegisterInfo *TRI = STI.getRegisterInfo();
 | 
						|
  const TargetInstrInfo *TII = STI.getInstrInfo();
 | 
						|
 | 
						|
  InstructionMapper Mapper;
 | 
						|
 | 
						|
  // Build instruction mappings for each function in the module.
 | 
						|
  for (Function &F : M) {
 | 
						|
    MachineFunction &MF = MMI.getMachineFunction(F);
 | 
						|
 | 
						|
    // Is the function empty? Safe to outline from?
 | 
						|
    if (F.empty() || !TII->isFunctionSafeToOutlineFrom(MF))
 | 
						|
      continue;
 | 
						|
 | 
						|
    // If it is, look at each MachineBasicBlock in the function.
 | 
						|
    for (MachineBasicBlock &MBB : MF) {
 | 
						|
 | 
						|
      // Is there anything in MBB?
 | 
						|
      if (MBB.empty())
 | 
						|
        continue;
 | 
						|
 | 
						|
      // If yes, map it.
 | 
						|
      Mapper.convertToUnsignedVec(MBB, *TRI, *TII);
 | 
						|
    }
 | 
						|
  }
 | 
						|
 | 
						|
  // Construct a suffix tree, use it to find candidates, and then outline them.
 | 
						|
  SuffixTree ST(Mapper.UnsignedVec);
 | 
						|
  std::vector<Candidate> CandidateList;
 | 
						|
  std::vector<OutlinedFunction> FunctionList;
 | 
						|
 | 
						|
  // Find all of the outlining candidates.
 | 
						|
  unsigned MaxCandidateLen =
 | 
						|
      buildCandidateList(CandidateList, FunctionList, ST, Mapper, *TII);
 | 
						|
 | 
						|
  // Remove candidates that overlap with other candidates.
 | 
						|
  pruneOverlaps(CandidateList, FunctionList, MaxCandidateLen, *TII);
 | 
						|
 | 
						|
  // Outline each of the candidates and return true if something was outlined.
 | 
						|
  return outline(M, CandidateList, FunctionList, Mapper);
 | 
						|
}
 |